49a^2-35a-6=0

Solution for 49a^2-35a-6=0 equation:

49a^2-35a-6=0

a = 49; b = -35; c = -6;
Δ = b2-4ac
Δ = -352-4·49·(-6)
Δ = 2401
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2401}=49$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-35)-49}{2*49}=\frac{-14}{98}
=-1/7
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-35)+49}{2*49}=\frac{84}{98}
=6/7
$